Jacksonville vs Sanford
Jacksonville, FL compared with Sanford, FL · 109 miles apart
Jacksonville has 1,017,689 residents to Sanford’s 67,483. Jacksonville comes out ahead on median household income, median rent, homeownership. Sanford does better on poverty rate, unemployment.
| Jacksonville, FL | Sanford, FL | |
|---|---|---|
| Population | 1,017,689 | 67,483 |
| Density (per sq mi) | 1,362 | 2,779 |
| Median household income | $69,872 | $66,891 |
| Median home value | $293,700 | $309,300 |
| Median rent | $1,465 | $1,609 |
| Homeownership | 57.6% | 52% |
| Average commute | 24.1 min | 25 min |
| Median age | 36.5 | 37.1 |
| Bachelor's degree + | 33.2% | 29.5% |
| Poverty rate | 14.5% | 11.9% |
| Unemployment | 4.6% | 4% |
| Price to income | 4.2× | 4.6× |
| Clear days a year | 27 | — |
| Days above 90°F | 42 | — |
Highlighted where one city is clearly better on that measure. Population, density, home value and median age carry no highlight — a higher number there is good or bad depending on what you want.
Full profiles
- Jacksonville, FLClimate, crime, housing
- Sanford, FLClimate, crime, housing